Explanation of Integer List with Sum Greater Than Target
Write a function to return the shortest list of consecutive integers whose sum is greater than a given target
.
This function uses a stack to find the point where the sum of consecutive integers exceeds the target
value.
Function Implementation
-
Initialize Stack and Sum Variable
:-
stack
: A stack to store consecutive integers. -
total
: The current sum of integers in the stack.
-
-
Iterate Through the Integer List
:-
Iterate over each integer in the given
numbers
list:-
Add the integer to the stack.
-
Add the current integer to the sum variable.
-
Stop the iteration as soon as the sum exceeds
target
.
-
-
-
Return the Result
:- Return the list of integers stored in the stack, which includes the shortest list of consecutive integers with a sum exceeding
target
.
- Return the list of integers stored in the stack, which includes the shortest list of consecutive integers with a sum exceeding
Example Solution
def solution(target, numbers):
stack = [] # Initialize stack
total = 0 # Initialize sum variable
for num in numbers: # Iterate through list
stack.append(num) # Add integer to stack
total += num # Update sum
if total > target: # Stop iteration if sum exceeds target
break
return stack # Return stack
Usage Example
Input and Output Example
print(solution(15, [1, 2, 3, 5, 7, 8])) # Output: [1, 2, 3, 5, 7]
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